Somebody help plz

1 ~ 45 lotto

Select 6

Ex) 1, 2, 3, 24, 35, 36 form

.

One digit numbers all different

.

1, 2, 3, 24, 35, 36

2, 3, 4, 25, 36, 31

…

3, 4, 5, 26, 31, 32

4, 5, 6, 23, 31, 32

.

Total number

6C3 x 3C2 x 1C1 = 20 x 3 x 1 = 60

If one lotto = 0.1 $

Total Chase = 6$

.

45C6 = 8145060

10C6 = 10C4 = 210

.

1 / 8145060 —-> 1/210

.

Could a more effective way be possible?

. ]]>

Dan, this is great! Even dimensions is fine. Even just dimension four is extremely interesting. I’d love to know some details. Please please send me (even partial handwritten things).

]]>Yes, but only in even dimensions.

]]>Thanks, I hope its ok on Terry Tao’s blog. Dan, are you involved in some topological high dimensional HEX?

]]>Sorry to be fussy, but shouldn’t this read more like

“… there is an injective polynomial map (P,Q) : ℚ → ℚ × ℚ”

?

]]>If the claim , ( I’m tempted to baptise it Tao’s Rational Jacobian Conjecture, TRJC for short!), is right, a natural idea is to look for a possible connection with the Jacobian conjecture for K=Q and n=2. W need such a P and Q to try to construct a Jacobian pair and prove the Jacobian conjecture in this case.

conversely, if Jacobian conjecture Jac(Q,2) is true, it woudl furnish all p’s answering TRJC.

But i guess proving Jac(Q,2) must be at leasta s hard as Jac(C,2, ( that my thesis supervisor Le Dung Trang claimed with C.Weber to prove in 1992, but all their results are wrong, although many published in French CRAS, Commentrai Helvetici and Kodai Journal 20 years later!!!)

Jac(C,2) is very hard to prove, ( but Jac(R,2) was proved false by Pinchuk!), and I remember having met Deligne in ICM 1994 and asked him if he can prove it. He told me he woudl write me, but never did.

PS: I’m sorry, my 1st comment was wrong! I’ll contact the administartrs to withdraw it. this 2nd comme,nt is more sound, ( I hope!), because I inadvertently did’nt see that P is a 2 variable, not 1, polynomial. Therefore, there is no direct link with Jac(C,1).

]]>